Trying to include randomly-selected HTML blocks via php - Webmaster Forums - Webmaster forum for HTML, PHP, ASP, CSS and more

abigailhamilton · 04-27-2010, 11:58 AM

I'm working on a simple php/html page that wants to include an external html file selected at random on load, from a group of 3. And I need help! The code I have is:

Code:

  <?php 

$randContent = array_rand('gift1.html', 'gift2.html', 'gift3.html'); 
include($randContent); 

?>

It's not working. I have gift1.html, etc. stored in the same folder. On execute, this is the error message I get, pertaining to the code above:

Quote:

Warning: Wrong parameter count for array_rand() in /home/content/p/e/r/perfectseason/html/giving-dyn.php on line 258

Warning: include() [function.include]: Failed opening '' for inclusion (include_path='.:/usr/local/php5/lib/php') in /home/content/p/e/r/perfectseason/html/giving-dyn.php on line 259

The page is online at theperfectseason-dot-com-slash-giving-dyn.php in case my hero-helper wants to look at the entire source.

bestynuan · 04-27-2010, 02:37 PM

you have the wrong syntax for array_rand..
it should be..

$pages = array('gift1.html', 'gift2.html', 'gift3.html');
$randIndex = array_rand($pages,1);
include($pages[$randIndex]);

array_rand returns the index of the element in the array..