PHPlot and Arrays - Webmaster Forums - Webmaster forum for HTML, PHP, ASP, CSS and more

andymsuk · 04-02-2009, 03:14 PM

Hi everyone.
I'm using PHPlot to draw graphs. Hopefully you are familiar with PHPlot. If not, here is a sample:

PHP Code:


			
$plot = new PHPlot();

 $data = array(

  array('', 1800,   5), array('', 1810,   7), array('', 1820,  10),

  array('', 1830,  13), array('', 1840,  17), array('', 1850,  23),

  array('', 1860,  31), array('', 1870,  39), array('', 1880,  50),

  array('', 1890,  63), array('', 1900,  76), array('', 1910,  92),

  array('', 1920, 106), array('', 1930, 123), array('', 1940, 132),

  array('', 1950, 151), array('', 1960, 179), array('', 1970, 203),

  array('', 1980, 227), array('', 1990, 249), array('', 2000, 281),

    );

$plot->SetDataValues($data);

$plot->SetDataType('data-data');

$plot->DrawGraph();

So, as you can see, the data used by the plotter is an array of arrays.
Now, my data I want to use for this is in a database, that I access through SQL.
Here's what I have so far:

PHP Code:


			
while($row = mysql_fetch_array($sql))

{

    $count = $count + 1;

    $Date = $row['Date'];

    $Mark = $row['Mark'];

    $blah = array('', $Date, $Mark);

    $graphdata[$count] = $blah;

};

$data = array($graphdata); //This bit is obviously instead of the example given above.

However, this doesn't seem to work and the graph image just returns the "corrupt image" X icon.

Can anyone spot what is wrong with my code or the right way to do it, please?

Thanks in advance.

Andy

dave.albert · 06-26-2009, 08:20 AM

Try something like

PHP Code:


			
$data = array(); 



$num = 0;



while ($row = mysql_fetch_assoc($result)) 

{

   $data[$num] = array($row["ins_group"],$row["los"]);

   $num += 1;   

}

Quote:

Originally Posted by andymsuk

Hi everyone.
I'm using PHPlot to draw graphs. Hopefully you are familiar with PHPlot.

PHP Code:


			
while($row = mysql_fetch_array($sql))

{

    $count = $count + 1;

    $Date = $row['Date'];

    $Mark = $row['Mark'];

    $blah = array('', $Date, $Mark);

    $graphdata[$count] = $blah;

};

$data = array($graphdata); //This bit is obviously instead of the example given above.

However, this doesn't seem to work and the graph image just returns the "corrupt image" X icon.

Can anyone spot what is wrong with my code or the right way to do it, please?

Thanks in advance.

Andy

danieljames123 · 05-04-2011, 02:50 AM

very good question