Test the value of a database field using conditional statement for empty - Webmaster Forums - Webmaster forum for HTML, PHP, ASP, CSS and more

ez2c · 09-20-2005, 05:28 PM

hi,
I am trying to test if a user enters nothing in a field in my db form the php script will enter something like ' not entered ' in this field in the db.
I tried something like below but get an error message. I know I need some type of conditional statement but don't know how to put it together.

if (some_array[some_field] != "")
{
do something
}

check to see if the field is empty or not. if it is empty, it'll put something there.

any help would be appreciated! thanks in advance!

ultan · 09-20-2005, 09:29 PM

Can you list the whole code so we can take a look at what may be the problem?

econ · 09-21-2005, 05:11 PM

It's safer to use empty().

PHP Code:


		
			
if($_POST['submit']) { 

   if((empty($_POST['field1'])) || (empty($_POST['field']))) { 

    echo "empty field"; 

     }  else { 

         // submit data 

         } 

} else { 



echo "FORM HERE"; 

// make sure you have 'name=submit' in your submit button 

}

cheers